no
$$\pm \frac{ \frac{ 1 }{ 2 } }{ \frac{ \sqrt{3} }{ 2 } }=\pm \frac{ 1 }{ \sqrt{3} }=\pm \frac{ \sqrt{3} }{ 3 } = \pm \frac{ 1.732 }{ 3 }=?$$

Question

no
$$\pm \frac{ \frac{ 1 }{ 2 } }{ \frac{ \sqrt{3} }{ 2 } }=\pm \frac{ 1 }{ \sqrt{3} }=\pm \frac{ \sqrt{3} }{ 3 } = \pm \frac{ 1.732 }{ 3  }=?$$

anonymous · Answer

$$\sin x=\frac{ 1 }{ 2 }$$
$$\sin ^2x+\cos ^2x=1,\cos ^2x=\frac{ 3 }{ 4 }$$
$$\cos x=\pm \frac{ \sqrt{3} }{ 2 }$$
$$\tan x=\pm ?$$

abb0t · Answer

When you have a square root, for example, you have $\sf \sqrt{3}$ what that actully is, is a exponent, so you have $\sf 3^{\color{red}{{\frac{1}{2}}}}$

abb0t · Answer

Oh, nevermind, ignore that.

Memorize, 

SOH
CAH
TOA

SOH = sine = opposite over hypotenuse
TOA = tan = opposite over adjacent
etc.,