A swimming pool charges $6 for adults and $4 for children. On a particular day, they made $1326 in admissions. If a total of 289 people paid to swim, there must have been ____ adults and _____ children.

Question

A swimming pool charges $6 for adults and $4 for children. On a particular day, they made $1326 in admissions. If a total of 289 people paid to swim, there must have been  ____  adults and  _____ children.

compassionate · Answer

Adults + Children = 1.326 

6a + 4c = 1.326 

This equation will give you the adults and children revenue 

The total number of people were 289 

Adults + Children = 289

So, the system becomes 

6a + 4c = 1,326 
a + c = 289 

now just solve the system.

anonymous · Answer

How do you solve the system?

jdoe0001 · Answer

hmm if you solve say.... a + c = 289     for  say   "c"    what do you get?

anonymous · Answer

I have no idea. I don't know how to figure it out.

jdoe0001 · Answer

hmmm you may want to brush up your linear simplication material then firstly

compassionate · Answer

a + c = 289 

i got bad news, Lauren, if you're having trouble solving for a, then you're really going to hate the process of elimination and substitution. a + c = 289. So solve, do the opposite. 

So a - c + c = 289 - c 
a = (289 - c) 

Now plug it into either equation and solve for a, then plug that back into it and completely solve c.