A bullet is fired through a board, 14 cm thick, with its line of motion perpendicular to the face of the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s, what is the acceleration (assume that it is constant) as it passes through the board

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blackstreet23 · Answer

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blackstreet23 · Answer

@ganeshie8

anonymous · Answer

$$v_f^2 = v_i^2 + 2a \Delta d$$

anonymous · Answer

Solve for a. Everything else is given.

the_beast_eli · Answer

It depends what the gun is and how close it was shot....