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Mathematics 19 Online
OpenStudy (james1769):

Add (3x4 − 2x3 + 1) + (12x4 + x2 − 11). (1 point) 15x4 − x3 − 10 15x4 − x2 − 10 15x4 − 2x3 + x2 + 10 15x4 − 2x3 + x2 − 10

Theoceangirl (the_ocean_girl):

need a walk through?

OpenStudy (james1769):

yes please

OpenStudy (james1769):

anyone?

Theoceangirl (the_ocean_girl):

sorry i was taking notes

Theoceangirl (the_ocean_girl):

i'm here to help walk you through

OpenStudy (james1769):

thnks

Theoceangirl (the_ocean_girl):

yup okay so first, do the multiplication inside the parentheses, but remember, the 2 in 2x3 is negative

OpenStudy (james1769):

ok

Theoceangirl (the_ocean_girl):

so after you do that, you combine all the numbers in the parentheses then you add the sums that are in the 2 sets of parentheses together do you understand it now?

OpenStudy (james1769):

kinda math isnt my friend

Theoceangirl (the_ocean_girl):

math is nobody's friend

OpenStudy (james1769):

nope

OpenStudy (james1769):

so the answer is d

Theoceangirl (the_ocean_girl):

yup!

OpenStudy (james1769):

thanks

Theoceangirl (the_ocean_girl):

no problem!

OpenStudy (james1769):

i have a few more if u want to help

Theoceangirl (the_ocean_girl):

sure

OpenStudy (james1769):

Subtract (5x2 + 3) −(2x2 + 4x − 12).

OpenStudy (james1769):

3x2 − 4x + 15 3x2 + 4x + 15 3x2 − 4x − 9 3x2 + 4x − 9

Theoceangirl (the_ocean_girl):

okay so same thing as before, but this time, you need to distribute the negative that's outside of the second set of parentheses basically, because of that negative, you have to multiply everything inside of that 2nd set of parentheses by -1 before anything else

OpenStudy (james1769):

do u add the exponents this is part of a dif qu

OpenStudy (james1769):

@the_ocean_girl help please

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