Question

Name at least 2 different ways you can solve the equation 5^(2x+1)=25

Answer 1

exponential...and i think logs

Answer 2

i have one method so far, which is solving by having equal bases is that right?

Answer 3

5^(2x+1)=25
5^(2x+1)=5^2
so 2x+1=2
2x=2-1
x=1/2

Answer 4

yes equal base ... same as exponent

Answer 5

im logs also

Answer 6

would you solve the problem the same way with logs? or do you solve it with different steps?

Answer 7

\[\log _{25}(5)=(2x+1)\]