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Physics 19 Online
OpenStudy (anonymous):

At t = 0 seconds, a cart is moving with a velocity of 10 cm/s and an acceleration of 4.0 (cm/s)/s. Assuming its acceleration stays at this value, what will its velocity be 7.0 seconds later?

OpenStudy (abhisar):

Hello!

OpenStudy (abhisar):

Are you familiar with equations of motion?

OpenStudy (anonymous):

Yeah. I just need someone to make sure I did it right. So it would be 4.0=(x-0)/7

OpenStudy (anonymous):

4*7=28 then you add in the 10 which gives you 38.

OpenStudy (anonymous):

Would that be right?

OpenStudy (anonymous):

Obviously there are units and such.

OpenStudy (abhisar):

Yes, that's right!

OpenStudy (anonymous):

Nice. Thank you!

OpenStudy (abhisar):

Welcome. About the units, you need to take care that everything is in similar unit system.

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

I have it written out but I didn't want to type all that out.

OpenStudy (anonymous):

No wonder it looks familiar.

OpenStudy (anonymous):

Yeah. I'm reviewing for a quiz and wanted to double check making sure I didn't forget how to do it.

OpenStudy (anonymous):

Ah, I see.

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