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if f(x)=x^3+ax^2+bx-3 and if f(1) =4 and f(-1)=-6 what is the value of 2a+b
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you can form 2 equations involving 'a' and 'b' from those two points they give you
2 equations/2 unknowns , solve able
x = 1 , y = f(1) = 4 x=-1, y = f(-1) = -6
well geesh, let them try it, don't just do it all for them.
That is the first, do the same for the second, and solve for the value of a and b 4 = 1^3 + a*(1)^2 +b*(1)-3
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a=6-b?
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