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Mathematics 17 Online
OpenStudy (anonymous):

how do i draw the graph for m (x)= x^2 + 4x + 9

OpenStudy (danjs):

do you se the general shape of it by the form , it is already in the general form

OpenStudy (danjs):

f(x) = ax^2 + bx + c general quadratic form, parabola

OpenStudy (anonymous):

how do i find the domain for the graph ? i factorized it and i got (x+2)^2 + 9

OpenStudy (danjs):

watch the completing the square there, you did that part right, but the constant 9 is wrong

OpenStudy (anonymous):

it says that x is a real number... obviously cuz the graph is infinity but it also says that x> a and i have to find the value of a.... how do i find a?

OpenStudy (danjs):

given m(x) = x^2 + 4x + 9 Graph the function and find the domain? what is it asking

OpenStudy (anonymous):

its asking the value of a

OpenStudy (anonymous):

in which x > a

OpenStudy (anonymous):

oh and i got the completing square... (x+2)^2 + 5

OpenStudy (danjs):

the domain of that is going to be all real numbers for possible values of X

OpenStudy (danjs):

It states that x is a real number because you want to exclude complex numbers or roots

OpenStudy (anonymous):

but how do i draw the graph...

OpenStudy (anonymous):

where will the intersection for the parabola be

OpenStudy (danjs):

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