Question

PLEASE HELP WILL FAN AND MEDAL!!!!!!!!!
Write the point-slope form of the equation of the line through the given point with the given
slope.
(-4,3) slope= -1
A) y+3=1/5(x+4)
B) y-3=-(x+4)
C) y-3=-2(x+4)
D) y+3=3(x-4)

Answer 1

You want to find the equation for a line that passes through the point (-4,3) and has a slope of -1.
First of all, remember what the equation of a line is:

y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was -1. So you can right away fill in the equation for a line somewhat to read:
y=-1x+b.
Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:
(-4,3). When x of the line is -4, y of the line must be 3.
Because you said the line passes through this point, right?
Now, look at our line's equation so far: . b is what we want, the -1 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-4,3).

So, why not plug in for x the number -4 and for y the number 3? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-4,3). y=mx+b or 3=-1 × -4+b, or solving for b: b=3-(-1)(-4). b=-1.
The equation of the line that passes through the point (-4,3) with a slope of -1
is

y=-1x-1


Is that all of the question?

http://www.webmath.com/equline2.html

Answer 2

oh my gosh thank you so much! I understand it now. you helped me so much!!!