Find four consecutive integers whose sum is between 55 and 73

Question

anonymous · Answer

Subtract 6 from all three sides
10<4x<18
Divide through by 4
10/4<x<18/4
2.5<x<4.5
The only two integers x between 2.5 and 4.5 are 3 and 4
So there are two sets:

x = 1st integer = 3
x+1 = 2nd integer = 4
x+2 = 3rd integer = 5
x+3 = 4th integer = 6
sum = 3+4+5+6=18

and

x = 1st integer = 4
x+1 = 2nd integer = 5
x+2 = 3rd integer = 6
x+3 = 4th integer = 7
sum = 4+5+6+7=22

Hope I helped ^^

anonymous · Answer

THANKS!

anonymous · Answer

No problemo :)

jaynator495 · Answer

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