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Chemistry 15 Online
pooja195 (pooja195):

@hwyl

pooja195 (pooja195):

@hwyl

pooja195 (pooja195):

http://prntscr.com/8kjg2c

OpenStudy (anonymous):

mass of bean group=average mass of one bean x number of each bean group So 375.91/243= 132.85/185= 227.35/192= Percent abundance=number of specific bean group/ total number of all bean group 243/(243+185+192) for the first one. You can do the two others. It'll eventually add up to 100% Multiply the answer you got from 6 and 7 (Average mass)(Percent abundance) for the 3 and add it together to find your total.

OpenStudy (hwyl):

do you still need help?

pooja195 (pooja195):

No. And thank you @Shalante :)

OpenStudy (anonymous):

No problem! Good luck on the rest.

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