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@hwyl
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@hwyl
mass of bean group=average mass of one bean x number of each bean group So 375.91/243= 132.85/185= 227.35/192= Percent abundance=number of specific bean group/ total number of all bean group 243/(243+185+192) for the first one. You can do the two others. It'll eventually add up to 100% Multiply the answer you got from 6 and 7 (Average mass)(Percent abundance) for the 3 and add it together to find your total.
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No. And thank you @Shalante :)
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