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Mathematics 11 Online
OpenStudy (calculusxy):

MEDAL!!!

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@Nnesha

OpenStudy (calculusxy):

@ybarrap

OpenStudy (freckles):

speed=distance/time

OpenStudy (freckles):

you are given the distance and you are given the amount of time

OpenStudy (calculusxy):

so would i have time be 4 1/3 hr?

OpenStudy (freckles):

\[20 \text{ minutes}=20 \text{minutes} \cdot \frac{1 \text{ hour }}{60 \text{ minutes}}=\frac{20}{60} \text{ hours }=\frac{1}{3} \text{ hours } \\ \text{ so you have she drove } 500 \text{ km } \text{ in } 4 \frac{1}{3} \text{hours }\] so you time thing is right you might consider it better to write as an improper fraction though

OpenStudy (freckles):

\[4 \frac{1}{3} \text{ hours}=\frac{13}{3} \text{ hours }\] or I guess a decimal would even work

OpenStudy (calculusxy):

ok i got it its b

OpenStudy (freckles):

\[\text{ so her speed was } \frac{500 km }{\frac{13}{3} hours }=500 \cdot \frac{3}{13} \frac{ km}{hr} = \frac{1500}{13} \frac{km}{hr}=115.4 \frac{km}{hr}\] yes b is the closest one

OpenStudy (freckles):

I should have put an approximation sign betwoo 1500/13 and 115.4

OpenStudy (freckles):

\[\text{ so her speed was } \frac{500 km }{\frac{13}{3} hours }=500 \cdot \frac{3}{13} \frac{ km}{hr} = \frac{1500}{13} \frac{km}{hr} \approx115.4 \frac{km}{hr}\]

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