HELP W? AN ACT PREP QUESTION< PLEASE I NEED TO DO WELL: A ramp for wheelchair access to the gym has a slope of 5% (that is, the ramp rises 5 feet vertically for every 100 feet of horizontal distance). The entire ramp is built on level ground, and the entrance to the gym is 2 feet above the ground. What is the horizontal distance, in get, between the ends of the ramp???
@Vocaloid
@jim_thompson5910 @amistre64 @pooja195 @satellite73
do you have a pic of the problem drawn out? or are you stuck on that part?
thats all of the problem and thats all it gives me
i have the answer choices but i really just need to know how to do it
well I meant in terms of you drawing it yourself (not having the teacher draw it for you)
i have an ACT prep book but sure
here's what the drawing would look like |dw:1443319000251:dw|
i just need to know the process, i already have the answer
oh ok thanks thats helpful
the info `A ramp for wheelchair access to the gym has a slope of 5% (that is, the ramp rises 5 feet vertically for every 100 feet of horizontal distance)` basically tells us that we'll have this proportion 2/x = 5/100
the numerators represent the vertical change in distance the denomiators represent the horizontal change in distance
ok
so you see how I got 2/x = 5/100? if so, then the next step is to isolate x
yep, I got that
ok tell me what x is
40
good
so thats the answer and how we do it?
like I said, solving 2/x = 5/100 for x
ok, thanks! I have another question! can i tag you in a new question and help me?
2/x = 5/100 2*100 = x*5 ... cross multiply 200 = 5x 5x = 200 5x/5 = 200/5 ... dividing both sides by 5 x = 40
ok! Can i make a new question and tag you in it?
sure
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