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Mathematics 13 Online
OpenStudy (mimi_x3):

how do i get this part

OpenStudy (mimi_x3):

I mean https://gyazo.com/cd7fd0d00bea9df5da158de7d6363c16

OpenStudy (mimi_x3):

like how do i derive the epsilon 0, 0

OpenStudy (anonymous):

it it \[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\sin(x)\cos(x)dx\]

OpenStudy (anonymous):

oh no i misread it

OpenStudy (anonymous):

\[\Psi_0=\cos(0)=1\]

OpenStudy (anonymous):

so i assume that the inner product is here is the integral right?

OpenStudy (anonymous):

\[\int_{-\pi}^{\pi}1dx=2\pi\]

OpenStudy (mimi_x3):

got it thanks

OpenStudy (anonymous):

yw

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