Question

(x^2-4x+3)-(3x^2-4x-3) is equivalent to:
2x^2-6
2x^2-8x
2x^2-8x-6
-2x^2+6
-2x^2-8x

Answer 1

@Vocaloid

Answer 2

start by distributing the negative sign

Answer 3

how do i do that

Answer 4

hint: -(A-B-C) = -A+B+C

Answer 5

oh ok gotcha

Answer 6

-(3x^2-4x-3) = ?

Answer 7

(3x^2+-4x+-3)?

Answer 8

almost, check your signs

Answer 9

oh, -3x^2+-4x+-3?

Answer 10

getting closer

Answer 11

-(-4x) = ?
-(-3) = ?

Answer 12

4x and 3!

Answer 13

right, so we have

- 3x^2 + 4x + 3 on the right side after we distribute


now we put the whole problem back together

Answer 14

yes

Answer 15

x^2-4x+3- 3x^2 + 4x + 3

know where to go from here?

Answer 16

just combine right?

Answer 17

yes, so what does that give us?

Answer 18

x^2+14-3x^2? Im really bad at combining like terms for some reason..

Answer 19

i most likely did it wrong

Answer 20

not quite

x^2 - 3x^2 = ?

Answer 21

3

Answer 22

so it would be x^+11?

Answer 23

uh, not quite

hint:

1 - 3 = -2
x - 3x = -2x
x^2 - 3x^2 = ?

Answer 24

just -2?

Answer 25

don't forget the x^2

Answer 26

-2^2???

Answer 27

im so bad at this one ...

Answer 28

nope, when you combine like terms, you keep the variable

x^2 - 3x^2 = -2x^2

Answer 29

plus 6 right?

Answer 30

right

Answer 31

think of it this way:

1 - 3 = -2
1 dollar - 3 dollars = -2 dollars

the "dollar" stays in the answer, just like x^2 stays in the answer

Answer 32

so our final answer is -2x^2 + 6

Answer 33

ok, im gonna need to practice that one a bit. thanks for all of you help! is it ok if i tag you in a couple of questions tomorrow?

Answer 34

sure, I'm online all day tomorrow

Answer 35

ok- thanks i will tag you !