Question

http://prntscr.com/8kypa6

Answer 1

@hartnn

Answer 2

X co-ordinate of the Vertex of \(y = ax^2+bx+c\) is just
\(\Large \dfrac{-b}{2a}\)

so first step will be to find a,b

compare
y = x^2 +6x+ 8
with
y = ax^2+bx+c

Answer 3

would my answers ba a and d?

Answer 4

'a' is correct :)

but since a= 1, b =6
using the formula, the x co-ordinate will be
\(\Large \dfrac{-b}{2a} = \dfrac{-6}{2(1)}\)

Answer 5

so 'a' and 'b' :)

Answer 6

oh ok thnx