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Mathematics 9 Online
OpenStudy (anonymous):

Send help pls

OpenStudy (anonymous):

OpenStudy (triciaal):

do you see this is a cubic function? the nth term is given as (n + 1)^3 we are doing the sum of a series the first SUM is 1 also the first term here (n + 1)^3 = 1 which gives n = 0 so k = 0 so we are finding the sum of the series (k + 1)^3 from k = 0 to the nth term (n + 1)^3

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