An electron in an excited state of a hydrogen atom emits two photons in succession, the first at 4050. nm and the second at 97.20 nm, to return to the ground state (n=1). For a given transition, the wavelength of the emitted photon corresponds to the difference in energy between the two energy levels.

What were the principal quantum numbers of the initial and intermediate excited states involved?

Question

An electron in an excited state of a hydrogen atom emits two photons in succession, the first at 4050. nm and the second at 97.20 nm, to return to the ground state (n=1). For a given transition, the wavelength of the emitted photon corresponds to the difference in energy between the two energy levels. 



What were the principal quantum numbers of the initial and intermediate excited states involved?

anonymous · Answer

In your book, look up, rydberg formula.

anonymous · Answer

You will be using that.