Question

Having trouble understanding these steps for one of my classes:

Answer 1

\[zl = \theta*z(h-l)-\theta*G\]

to

\[zl*(1+ \theta) = \theta*zh-\theta*G\]

to

\[l = \theta/(1+\theta)*(h-G/z)\]

Answer 2

Where all are constants except l

Answer 3

Okay I get that, thanks a lot. Can you explain the last part too for us?

Answer 4

hmmm what part again?

Answer 5

From zl(1+Theta) = Thetazh -ThetaG to the answer where l is solved for

Answer 6

l=θ/(1+θ)∗(h−G/z) is the right answer

Answer 7

hmmm

Answer 8

sec

Answer 9

No problem appreciate the help friend

Answer 10

hmmm hmm lemme start off

you want \(\bf zl = \theta*z(h-l)-\theta*G\qquad to\qquad
l = \cfrac{\theta}{1+\theta}\cdot \cfrac{h-G}{z}\)

right?

Answer 11

yes