Question

Which of the following shows 2x3y − 3x2 + 7y2x − 12y written in standard form?

2x3y + 7y2x − 3x2 − 12y
−12y + 7y2x − 3x2 + 2x3y
7y2x − 12y + 2x3y − 3x2
−12y − 3x2 + 7y2x + 2x3y

Answer 1

for each term, add the exponents together

Answer 2

then order the terms from highest exponent sum to least

Answer 3

\[2x ^{3} y − 3x ^{2} + 7y ^{2} x − 12y\]

Answer 4

2x^3 * y ---> 3 + 1 = 4
3x^2 ---> 2
7yx^2 ---> 3
12y ---> 1

so the order is

2x^3y + 7yx^2 - 3x^2 + 12y

Answer 5

*-12y

Answer 6

Thank you