Question

Topic: Projections and Minimum Distance

Use a projection to find the distance from the point to the plane Q(0, 2, -1), plane \(\sf 2x_1-x_3=5\).

Answer 1

i know that normal vector would be.. <2,0,-1>

Answer 2

and then...pick a point from the plane..

when x1 is 0, then x3 must be equal to -5.. so my point P would be P<0,0,-5>

Answer 3

then what?

Answer 4

PQ would be <0-0, 2-0, -1+5>= <0,2,4>