10. The sides of the triangle are 40 cm, 50 cm, and 60 cm. How far is the point of intersection of the perpendicular bisector of the sides of the triangle to any of its vertex?

Question

10.	The sides of the triangle are 40 cm, 50 cm, and 60 cm. How far is the point of intersection of the perpendicular bisector of the sides of the triangle to any of its vertex?

anonymous · Answer

it is radius of circumcircle.
$$R=\frac{ abc }{ 4~ area~ of~ \triangle }$$

anonymous · Answer

area of triangle$$=\sqrt{s \left( s-a \right)\left( s-b \right)\left( s-c \right)}$$
where a,b,c are sides of triangle.
and 2s=a+b+c

marco26 · Answer

ok thanks, I get it now :)

anonymous · Answer

yw