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OpenStudy (texaschic101):
-2 >= x/27 --- multiply both sides by 27
-54 >= x
if there is an equal sign in the problem, it will be a closed circle....and greater then means shaded to the right. So what do you think now ?
OpenStudy (texaschic101):
oh...wait...it can also be x <= -54...so it is less then (shaded to the left)
OpenStudy (anonymous):
it would be C
OpenStudy (texaschic101):
yes..it is C
OpenStudy (anonymous):
:) i knew it
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13r <= -156 --- divide both sides by 13
r <= -156/13
r <= - 12
so r is less then or equal to -12
closed circle, shaded to the left
so what do you think now ?
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OpenStudy (anonymous):
automatically crosses out C/D there going >
OpenStudy (anonymous):
A :)
OpenStudy (texaschic101):
crosses out b too.....because of the equal sign....it needs a closed circle
OpenStudy (anonymous):
A :)
OpenStudy (texaschic101):
yep ^^
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ok....you got an open circle...means there is no equal sign in the problem....that eliminates D. It is shaded to the left....that means less then...that eliminates C. Your open circle is on 2....so that means x is less then 2.....answer is B. Understand ?
OpenStudy (texaschic101):
These can be easily done by process of elimination
OpenStudy (anonymous):
hmm
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ok...she does not want to spend MORE THEN $50. That means she can spend 50 or less.
So it would be x <= 50.....you have to include the = sign because she can still spend 50.
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OpenStudy (anonymous):
D :)
OpenStudy (texaschic101):
the other 2 ??
OpenStudy (anonymous):
i ment C
OpenStudy (anonymous):
not D
OpenStudy (texaschic101):
no...it is D
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x + 1/4 >= 5/8 --- subtract 1/4 from both sides
x >= 5/8 - 1/4 -- common denominator is 8
x >= 5/8 - 2/8
x >= 3/8
equal sign means closed circle....greater then means shaded to the right.
answer is B
x > 1 3/4
no equal sign, so an open circle....greater then means shaded to the right...answer is D.
do you have any questions on anything that I have done ?
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OpenStudy (anonymous):
i got 100% :)
OpenStudy (texaschic101):
Thats what I am talking about :)....way to go.
OpenStudy (texaschic101):
congrads.....gonna go help someone else now. Tag me if you need any more help :)