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OpenStudy (anonymous):
how would you solve 4cos2A = 3cosA for 90º≤A≤180º.
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OpenStudy (thomas5267):
\[ 4\cos(2A)=4\cos^2(A)-4\sin^2(A)=4\cos^2(x)-4\left(1-\cos^2(x)\right)\\ =8\cos^2(x)-4 \]
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