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Rate of change -Differentiation An inverted cone with a base area of 2500pi mm^2 and height of 300m is slowly being filled with water. Water is being poured in at a rate of 350 mm^3/s. At what rate is the height of the water changing when the water is 100mm from the top of the inverted cone?
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I think: We are to find out: \[\frac{ dh }{ dt } \] We know \[\frac{ dV }{ dt }=350\]
|dw:1443476761216:dw|
Volume of cone: \[V=\frac{ 1 }{ 3 }\pi r^2h\] Volume of this cone:\[V=\frac{ 2500 }{ 3 }h\]
use "similar triangles" to write r in terms of h
from the area of the base you find r=50 and you have this |dw:1443477912255:dw|
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