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Physics 18 Online
OpenStudy (anonymous):

quick question making sure my answer is correct.

OpenStudy (anonymous):

http://imgur.com/iawJOzv

OpenStudy (anonymous):

simplifying it away from \[Q=Q_0e^{-(t/RC)}\]\[t=-RC*\ln(1/3)\]

OpenStudy (anonymous):

\[t=-(1.0*10^6ohms)(0.05F)*\ln(1/3)\]\[t=23856.1s\]\[t=397.6minutes\]

OpenStudy (irishboy123):

use natural log: ie \(ln\) you are currently using \(log_{10}\)

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