Question

Can someone tell me if my answer to this is correct?

Answer 1

\[\sum_{n=1}^{3}(n^2-2) = 8\]

Answer 2

Yup thats correct

Answer 3

\[\sum_{n=1}^{3}(n^2-2)=(1^2-2) + (2^2-2)+(3^2-2) = (1-2)+(4-2)+(9-2)\]\[ = -1+2+7=8\checkmark\]

Answer 4

Thanks! I just wanted to make sure I remember the method correctly.

Answer 5

Whether you did or not, you got the correct answer :-)