Question

The length of a rectangle is four times its width.
If the area of the rectangle is
100

ft2
, find its perimeter.

Answer 1

l=4w
100=4w*w
100=4(w)square
w=5
perimeter=2(l+w)
p=2(25)
p=50

Answer 2

Area = width* length
if the unknown width is "x"
then the length is "4x"
area = 100 = 4x *x
\[4x ^{2} =100\]
\[x ^{2} = 25\]
\[x =5\]
So the width is 5
and the length is 4*5 = 20
Perimeter = length *2 +width *2
permiter = (20 *2 ) + (5*2)
= 40 +10 = 50