The length of a rectangle is four times its width.
If the area of the rectangle is
100

ft2
, find its perimeter.

Question

The length of a rectangle is four times its width. 
If the area of the rectangle is 
100
 
ft2
, find its perimeter.

anonymous · Answer

l=4w
100=4w*w
100=4(w)square
w=5
perimeter=2(l+w)
p=2(25)
p=50

rushwr · Answer

Area = width* length
if the unknown width is "x"
then the length is "4x"
area = 100 = 4x *x 
$$4x ^{2} =100$$
$$x ^{2} = 25$$
$$x =5$$
So the width is 5
and the length is 4*5 = 20
Perimeter = length *2 +width *2 
permiter = (20 *2 ) + (5*2)
               = 40 +10 = 50