Mathematics
6 Online
OpenStudy (anonymous):
What is the value of the expression 8–2? The 2 is a small number.
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OpenStudy (steve816):
8 - 2 = 6
OpenStudy (anonymous):
stop.
OpenStudy (steve816):
?
OpenStudy (anonymous):
Bump
OpenStudy (anonymous):
@marco26
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OpenStudy (anonymous):
Can you help?
OpenStudy (anonymous):
Need help anyone?
OpenStudy (anonymous):
I need help yo
OpenStudy (anonymous):
@Black_ninja123
imqwerty (imqwerty):
ok so 8-2 means that ur subtracting 2 from 8
for example if u got 8 chocolates and i came and stole 2 of them then how many wuld be left with u :)
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OpenStudy (anonymous):
No no no no.
OpenStudy (anonymous):
8-2 the 2 is a small number that is high
imqwerty (imqwerty):
nononono
imqwerty (imqwerty):
u jst want the answer :P
OpenStudy (anonymous):
Look What is the value of the expression 8–2?
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imqwerty (imqwerty):
its 100
OpenStudy (anonymous):
The 2 is a small number
imqwerty (imqwerty):
yes 2 is smaller so what
OpenStudy (anonymous):
Look stay here I'll post a pic
of what the 2 looks like
imqwerty (imqwerty):
ok :) please post a HDR pic cause i can't see what 2 looks like vry well :)
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OpenStudy (anonymous):
See?
OpenStudy (anonymous):
Can you help?
imqwerty (imqwerty):
oh :) its\[8^\left( -2 \right)\] ok :)
lol i thought u were kiddin XD
OpenStudy (drummergirl3):
lol
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OpenStudy (anonymous):
How did you make the 2 look like taht
OpenStudy (anonymous):
So it will be alot easier for me to explain
imqwerty (imqwerty):
ok try to use this identity-
\[a^\left( -b \right)=\frac{ 1 }{ a^b }\]
i used the equation tool to do that :)
OpenStudy (anonymous):
What is it under?
OpenStudy (rushwr):
\[8^{-2} = \frac{ 1 }{ 8^{2} } = \frac{ 1 }{ 64}\]
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OpenStudy (anonymous):
Rush
OpenStudy (anonymous):
Can you help me out with 4 more? WIll give you medals
OpenStudy (anonymous):
@Rushwr
imqwerty (imqwerty):
( ͡° ͜ʖ ͡°)
OpenStudy (anonymous):
Qwerty
where is the smal letter thing in equations
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OpenStudy (rushwr):
yeah yeah @dredayAJO
OpenStudy (anonymous):
Rushwr
OpenStudy (anonymous):
@Rushwr
OpenStudy (rushwr):
yh
OpenStudy (anonymous):
Can you help with 4 questions?
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