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An airplane, initially moving at 3.0 m/s along a runway, begins to accelerate at 3.6 m/s2. How far down the runway will it be in 20. seconds?
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(v-u)/t =a u= 3 m/s a = 3.6 m/s^2 t=2 s
if u put in the above relation u will get the answer..............
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you may use the formula : \[s= ut + \dfrac{1}{2}at^2\]
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