Question

Simplify: \(\sf sin(tan^{-1}x)\)

Answer 1

answer is \(\sf \large \frac{x}{1+x^2}\)

Answer 2

idk how they get it

Answer 3

correction, answer is \(\sf \large \frac{x}{\sqrt{1+x^2}}\)

Answer 4

@triciaal @Loser66 @Nnesha

Answer 5

we can draw a right triangle
tan = opposite over adjacent
so arctan x is same as x/1 \[\huge\rm \tan \theta =\frac{ opposite }{ adjacent }=\frac{ x }{ 1 }\]

Answer 6

apply the Pythagorean theorem to find 3rd side of right triangle

Answer 7

thanks! got it :)

Answer 8

np :=0

Answer 9

:=)*