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If $192x^2 -16 = 0$, find the value of $\frac{1}{x^4}$. PLEASE HELP
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can anybody help me...
can u rewrite the problem?
\[192x^2-16=0 \text{ solve this for } x^2\]
let me know when you have done that and there will be two more steps hints to the next two steps: after solving for x^2, square both sides of the equation after that, take the reciprocal of both sides of the equation
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