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(x - 5)(2x) = (x - 5)(4)
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can I just cross out (x - 5) on both sides?
Don't distribute anything
No you can't Cross out the x-5 's
Do It the way I showed you earlier.
Im talking about divide both sides by (x - 5)
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No, don't do that either. That's not a legal step. You can't divide by the Variable you're solving for.
but 2x is left over to solve for tho...
Here's an example of what to do:
look at the problem, its different lol
the principle is the same start by subtracting (x - 5)(4) from each side to get (x - 5)(2x) - (x - 5)(4) = 0
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then factor. (x-5)[2x - 4] = 0 then solve for x
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