Question

64- a2

Answer 1

Huh?

Answer 2

64 + \[a^{2}\]

Answer 3

??\

Answer 4

64- a2

If the task is to factor the posted expression, note that it is the difference of two squares.

Answer 5

64- a2 = 8^2 - a^2

The factoring pattern for the difference of two squares is:

(a^2 - b^2) = (a + b)*(a - b)

Answer 6

Lol, Thank lord somone is helping. I couldn't even read when he wrote it out.

Answer 7

In your problem, a is 8 and b is a.

(a^2 - b^2) = (a + b)*(a - b)

64- a2 = 8^2 - a^2 = ( 8 + a) * ( ? - ?)

@ak123

Answer 8

@Defiance I am assuming that the instructions are to factor the expression posted. So, my posts may be irrelevant. :)