Question

How to 'reverse' an exponent? Do I use ln?

Answer 1

Trying to solve FOR epiLson in I=Io10^(-episilon(J)L)

Answer 2

This is the Beer-Lambert Law.

Answer 3

\[\frac{ 1 }{ a ^{2}} = a ^{-2}\]

Answer 4

It's the change of the sign of the exponent :)

Answer 5

realized I asked the wrng questin...