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I need help on limits. Can someone help me? Thanks.
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Given\[x^2+4x \le f(x)\le -x^2-4x,-4\le x \le 0\] can the squeeze theorem be applied to find \[\lim x \rightarrow-2 f(x)\] ?
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what do you get if you put in x=-2 into both sides? I get -4 <= f(-2) <= 4 that is a big range for f(-2), we don't really know its value, do we? if it were 0<= f(0) <= 0 for example we see f(0) is "between" 0 and 0, so must be 0. that is a real squeeze
Oh all you had to do was plug it in... wow I was going around it the hard way. Thanks!
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