Question

please help

The length of a rectangle is 8 in. more than its width. The perimeter is 52 in.

What is the length of the rectangle?

Answer 1

The perimeter of the rectange is equal to:
P=2*(width + length)=2(W + L)
We know that length is 8 in more than width, so L=W + 8 in. We also know that P=52in.
So here is our equation:
52=2(W + W + 8)
Now simplify

Answer 2

are we figuring out W? if so w = 9

Answer 3

Combine like terms in brackets: 52=2(2W+8)
Divide both sides by 2: 52/2 = 2/2(2W+8)
Simplify: 26=2W+8
Subtract 8 from both sides: 26-8=2W+8-8
Simplify: 18=2W
Divide both sides by 2: 18/2=2W/2
Simplify: 9=W

We got that width is 9 inches. So now solve for length: L=W+8
L=9+8=17 Inches

The Answer is: The length of the rectangle is 17 inches

Answer 4

We could figure out L directly, by wrting W=L-8 inches instead of L=W+8 inches and so we will have another equation, but the answer will be the same

Answer 5

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Answer 6

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Answer 7

*best response