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@Nnesha Did I graph these 3 points, right?
hmm \[\huge\rm y=a(x-h)^2+k\] vertex form of parabola where (h,k) is the vertex point and find x and y intercepts
x-intercept is a point where line intersect x-axis when y=0 so substitute y for 0 to find x intercept y-intercept is a point where line intersect y-axis when x=0 so substitute x for y to find y-intercept
The vertex is (4,1)
right
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what are the next steps?
alright and bec a is negative in the question so we would get max point (graph opens down)
so max would be at ((4,1) |dw:1443814926678:dw|
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