Question

Find a solution to the following system of equations.
mc002-1.jpg
mc002-2.jpg

A. (-8, -15)
B. (0,1)
C.(-2, -15)
D.(2,5)

Answer 1

-5x+y=-5
-4x+2y=2

for the images

Answer 2

@IrishBoy123
@Jemurray3 @wio @Broskishelleh

Answer 3

this guy needs halp ;p

Answer 4

@haleyelizabeth2017

Answer 5

Plug in y=5x-5 (-5x+y=-5 add 5x to both sides) for y in the second equation:

-4x+2(5x-5)=2

Think you can do that? Then, just plug in the value you get for x into y=5x-5 and solve for y.

Answer 6

so do i do 5+5 and -5+5?

Answer 7

5+5=10 -5+5=0

Answer 8

a maybe

Answer 9

no lol...

Answer 10

my apologies, I'm getting help on my own math lol so...
-4x+2(5x-5)=2
-4x+10x-10=2

Think you can take it from there?

Answer 11

i keep getting an answer thats not on my answer choices.. lol

Answer 12

\(-5x+y=-5\)
\(-4x+2y=2\)
change (Multiply with - )
\(+4x-2y=-2\)

Then,
\(-5x+y=-5\)
\(+4x-2y=-2\)
solution:
\(x-y=7\)


option \(D\)
\(2-(-5)=7\)

Answer 13

@mckenzieandjesus Check it before you copy.

Answer 14

\(NOTE:\) It's just a model... i have purposefully done wrong

Answer 15

huh?

Answer 16

so option d isnt right?

Answer 17

Time up:
\(-5x+y=-5\)
\(+4x-2y=-2\)
Solution:
\(-x-y=-7\)

substitute, Option D.(2,5)
\(2 \) = \(x\)
\(5 \) = \(y\)


Substitute: \(-x-y=-7\)
\(-2-5~=~7\)

\(you~are~right~!!\) @mckenzieandjesus

Answer 18

\(**error: ~ -2-5~=~-7\)

Answer 19

U ALWAYS HAVE ERRORS \(BANG\)

Answer 20

\(freddy laugh\)

Answer 21

?

Answer 22

Five Nights At Freddy's never heard of it?