Question

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Answer 1

hmmm is actually -2 . so \(\bf \textit{vertex of a parabola}\\ \quad \\
y = {\color{red}{ -2}}x^2{\color{blue}{ +12}}x{\color{green}{ -11}}\qquad

\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)

Answer 2

\(\bf \textit{vertex of a parabola}\\ \quad \\
y = {\color{red}{ 2}}x^2{\color{blue}{ +28}}x{\color{green}{ -12}}\qquad

\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)

Answer 3

:)