Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

help me check my answer? whats the inequality for this graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

i think its >=x+2

OpenStudy (anonymous):

thats supposed to be y>=x+2

jimthompson5910 (jim_thompson5910):

the V shape implies we have an absolute value

OpenStudy (anonymous):

y>=|x+2|

jimthompson5910 (jim_thompson5910):

good

OpenStudy (anonymous):

my answer is correct?

OpenStudy (triciaal):

yes

OpenStudy (anonymous):

thank you, will you help me with another?

jimthompson5910 (jim_thompson5910):

go ahead

OpenStudy (anonymous):

i think its y>|x-3|

jimthompson5910 (jim_thompson5910):

it's hard to tell if the boundary is dashed or not, but I agree with the rest

OpenStudy (anonymous):

its dashed

jimthompson5910 (jim_thompson5910):

ok yeah, you have the right answer

OpenStudy (anonymous):

and this one? its really confusing

OpenStudy (anonymous):

the line isnt dashed

OpenStudy (anonymous):

would it be \[y<-\sqrt{x}+1\]

jimthompson5910 (jim_thompson5910):

looks great. Nice work

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!