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Mathematics 20 Online
OpenStudy (janu16):

What is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?

OpenStudy (janu16):

@AlexandervonHumboldt2

OpenStudy (alexandervonhumboldt2):

ok so |dw:1443885390273:dw|

OpenStudy (alexandervonhumboldt2):

|dw:1443885459543:dw|

OpenStudy (janu16):

yeaa

OpenStudy (alexandervonhumboldt2):

(6-2)/2=4/2=2 => 2+2=4 => vertex is (5,4) b will be the distance between the vertex and the directrix or focus. |dw:1443885604489:dw| (x−h)^2=4b(y−k) ((h,k) is vertex ) b=2 (h,k)=(5,4) Plug and get this equation: (x−5)^2=8(y−4) now simplify this equation and find your answer

OpenStudy (alexandervonhumboldt2):

simplifying is easy

OpenStudy (janu16):

−one eighth (x − 5)2 + 4?

OpenStudy (janu16):

wait one eighth (x − 5)2 + 4

OpenStudy (alexandervonhumboldt2):

yeah 1/8*(x-5)^2+4=y

OpenStudy (janu16):

okk thx!

OpenStudy (alexandervonhumboldt2):

np

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