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The following graph of f(x)=x^2 has been shifted into the form f(x)=(x-h)^2+k
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This
in that equation (h,k) is the vertex point
ya so im lookinf for k
y-coordinate of the vertex would be the k |dw:1443886284134:dw| so look at the graph find what's x and y
2?
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it should be (x,y) pair
2,2? not sure
you can draw a vertical line like this |dw:1443886489382:dw| when x = 2 y =-1 so (2,-1)
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