Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (janu16):

The following graph of f(x)=x^2 has been shifted into the form f(x)=(x-h)^2+k

OpenStudy (janu16):

This

Nnesha (nnesha):

in that equation (h,k) is the vertex point

OpenStudy (janu16):

ya so im lookinf for k

Nnesha (nnesha):

y-coordinate of the vertex would be the k |dw:1443886284134:dw| so look at the graph find what's x and y

OpenStudy (janu16):

2?

Nnesha (nnesha):

it should be (x,y) pair

OpenStudy (janu16):

2,2? not sure

Nnesha (nnesha):

you can draw a vertical line like this |dw:1443886489382:dw| when x = 2 y =-1 so (2,-1)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!