Stanford University's soccer field has an area of 8800 square yards. Its length is 30 yards longer than its width.
1. Write an expression for each dimension (length and width) of the soccer field.
2.Write an equation and solve for the dimensions of the soccer field.
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Vocaloid (vocaloid):
let length = L
and width = W, with me so far?
OpenStudy (hugy0212):
yes
Vocaloid (vocaloid):
"length is 30 yards longer than its width. "
means that L = 30 + W
so length = 30 + W
and width = W, that takes care of #1
Vocaloid (vocaloid):
for #2, we let length*width = area
so
W(W+30) = 8800
solve for W
OpenStudy (hugy0212):
Do I distribute the W ?
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Vocaloid (vocaloid):
yes
OpenStudy (hugy0212):
W^2+30W=8800
Vocaloid (vocaloid):
good, now subtract 8800 from each side
OpenStudy (hugy0212):
Is it -8800W^2-8770W?
Vocaloid (vocaloid):
nope
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Vocaloid (vocaloid):
remember that you cannot combine numbers and variables
Vocaloid (vocaloid):
W^2+30W-8800=0
OpenStudy (hugy0212):
So it'll be W^2+30W-8800
Vocaloid (vocaloid):
yes, now factor
Vocaloid (vocaloid):
W^2+30W-8800 = ?
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OpenStudy (hugy0212):
can and 10 and 880 work?
Vocaloid (vocaloid):
nope, think carefully
our two factors must add to 30 and multiply to get 8800
Vocaloid (vocaloid):
W^2+30W-8800 = (W+110)(W-80), know where to go from here?
OpenStudy (hugy0212):
Do i solve for W?
Vocaloid (vocaloid):
yes
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OpenStudy (hugy0212):
W=-110 and W=80
Vocaloid (vocaloid):
good, now remember that W is width, and width must be positive
so W = 80
Vocaloid (vocaloid):
now find L
OpenStudy (hugy0212):
L=110
Vocaloid (vocaloid):
good! that should b everything
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