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here, we have to write the inverse matrix of this matrix: \[\left( {\begin{array}{*{20}{c}} { - 1}&4 \\ 7&{ - 1} \end{array}} \right)\]
Ok and then what?
such inverse matrix is: \[\frac{1}{{27}}\left( {\begin{array}{*{20}{c}} 1&4 \\ 7&1 \end{array}} \right)\]
Ohh so the answer is A?
yes!
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