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The coefficient of friction are µs = 0.4 and µK = 0.3 between all surfaces in contact. Determine the smallest force P required to start the 30 kg block moving if cable AB (a) is attached as shown (b) is removed
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need help with these three questions
sorry, my word has crashed, can you make a sketch of your exercise, please?
wait please
part (b) the cable is removed In this case total friction force, acting on composed block is: \[{\mu _s}\left( {{m_A} + {m_B}} \right)g\] where \(\mu_s\) is the friction coefficient between the composed block and the plane, whereas \(m_A\) and \(m_B\) are the masses of the two blocks
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