Question

Find the equation to the tangent line to the curve x^2 (2-x)-y^2 =0

Answer 1

\[x ^{2}(2-x) - y ^{2}\]

Answer 2

\[y=\sqrt{2x^2-x^3}\]

Answer 3

\[\frac{ dy }{ dx }=\frac{ 1\left( 4x-3x^2 \right) }{ 2\sqrt{2x^2-x^3} }\]

Answer 4

find x,and then y
eq. of tangent is y-?=dy/dx(x-?)