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If y^-3x=27, compute exactly 7^2x+1
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y^(-3x)=27, compute exactly 7^(2x)+1?
7^(2x+1)
So then you need to figure out x and then plug that x-value into \(7^{2x}+1\) ?
the +1 is part of the exponent
and yes i believe so
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infinite solutions
what would be the steps to attempt to solve this though
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