Question

I need help with math questions can someone inbox me please

Answer 1

It's a picture of math question how do I post it

Answer 2

@bella280 you can use the "attach file" button located at the bottom of the text box here! :)

Answer 3

There's none :( I'm doing it from my cell phone. Do I need to get on a computer to attach a file?

Answer 4

oh... probably :c

Answer 5

Okay I'm going to try right now

Answer 6

first file is numbers 10-21
second file is numbers 28-31
third file is numbers 24-39

Answer 7

Hold on, Im gonna repost the images :)
It's really bugging me that they're rotated lol

Answer 8

sorry about that. thank you so much

Answer 9

i had to send them for my cell phone to the computer. so the pictures got rotated for some weird reason. sorry again about that

Answer 10

So these guys, ya? :d

Answer 11

yes those are the questions would you be able to help me with them

Answer 12

and wow ur amazing with fixing pictures.

Answer 13

\[\large\rm 3y\sqrt{98}+15y \sqrt2\]With this type of problem,
they usually want you to try and get both roots in terms of the smaller one.
So here, we'd like to write both as a \(\large\rm \sqrt2\) if we are able to.

I'll show you how we can do that with the 98,\[\large\rm \sqrt{98}=\sqrt{49\cdot2}=\sqrt{49}\cdot\sqrt2=7\cdot2\]What I'm doing is:
I'm writing 98 as 49*2,
then im writing them as separate roots, because the 49 can come out of the root.

Answer 14

Woops! typo on that last step :)

Answer 15

\[\large\rm \color{orangered}{\sqrt{49}}\cdot\sqrt2=\color{orangered}{7}\cdot\sqrt{2}\]

Answer 16

would you actually be able to give me all the answers to the problems. because i just want to check my work. please

Answer 17

no sorry :c

Answer 18

:( please i know im a stranger and all its just im so stressed out and im studying for a bug exam tomorrow. it would mean the world to me

Answer 19

I can show you how to do a few of them :O
I'm not gonna do your homework for you though XD lol

\[\large\rm 3y\color{orangered}{\sqrt{98}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49\cdot2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\sqrt{49}\cdot\sqrt{2}}+15y \sqrt2\]\[\large\rm 3y\color{orangered}{\cdot7\cdot\sqrt{2}}+15y \sqrt2\]Multiply the 7 and 3,\[\large\rm 21y \sqrt2+15y \sqrt2\]Think of y sqrt(2) as your ..thing.
\(\large\rm y\sqrt2=apple\)

So the problem is really just\[\large\rm 21apples+15apples\]So we get\[\large\rm 36apples=36y \sqrt2\]for our answer.

Answer 20

okay can u do like 5 of them questions