Question

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Answer 1

@jim_thompson5910

Answer 2

\[\Large \triangle ABD \cong \triangle FEC\]

so

\[\Large \angle ADB \cong \angle FCE\]

Answer 3

And since those two angles are congruent, then finding the third angle for the tiny triangle should be easy \(180^\circ = 45^\circ + 45^\circ + \theta\)